Question

the length of a rectangle is 2 meters more than its width. if the area is 63 square meters, what are the length and width?

Answer 1

length=2+ width
now area of rectangle= (length)(width)= 63

Answer 2

\[l=2+w\]
\[A=lw=63\]

Answer 3

(2+width)*width=63
w^2+2w-63=0 can you do it now?

Answer 4

(w+9)(w-7)=0
w=9,7

Answer 5

@RenaeMonroe ??

Answer 6

9*7 =63 and 7+2=9

Answer 7

how did you get 9,7 ???

Answer 8

by solving and factorizing \[w^2+2w-63=0\]

Answer 9

\[w^2+9w-7w-63=(w+9)(w-7)\]

Answer 10

k i see

Answer 11

hope that helps you

Answer 12

it has thank you
let me see if i can find the length and width
then i will post it and you can tell me if it is right or wrong

Answer 13

sure

Answer 14

ok im lost i cant figure out what to do

Answer 15

see you got w=-9,7 so -9 can't be a length therefore 7=width

Answer 16

where did you get -9

Answer 17

see we have (w+9)(w-7)=0 therefore w =-9 and 7

Answer 18

ok so i have a=l*w
63=(w+2)*w
63=w^2+2w
0=w^2+2w-63
0=(w-7)(w+9)
w-7=0 or w+9=0
w=7 or w=-9
but -9 wont work because you can not have a negative length so the only right answer is w=7
is this right

Answer 19

yes correct

Answer 20

thank you for helping

Answer 21

:) YW