Question

Solve the following system

x-3y = 10
2x+y = 13

Answer 1

x-3y = 10--> x = 10+3y
Plug in for x.....2(10+3y) + y = 13---->20 + 7y = 13

Solving for y gives -1. Plug that in for y and solve it.

Answer 2

x-3y = 10
2x+y = 13

2{x-3y}=(2)(10)
-(2x+y)=(-1)(13)

2x - 6y = 20
-2x-y = -13

add them up
-7y = 7
y = -1

substitute y =-1 to one of them
x-3(-1)=10
x+4 = 10
x = 6

Answer 3

So the answer is

x=7
y=-1

Correct?

Answer 4

@franciscanmonk I think you made a mistake here x-3(-1)=10

Answer 5

Yep, that's correct joker @thejoker1177