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OpenStudy (anonymous):
Why is \(\Delta q = \lambda\)? Let's say I'm measuring an electron's position with light. I agree that \(\Delta p = h/\lambda\), where \(\lambda\) is the wavelength of light that I use. But how does that lead to the HUP?
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OpenStudy (anonymous):
experimentX's link did the job. http://spiff.rit.edu/classes/phys314/lectures/heis/heis.html
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