Mathematics
7 Online
OpenStudy (anonymous):
Simplify the following:
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OpenStudy (anonymous):
\[\frac{ 3a }{ a+3 } - \frac{ (a-4) }{ a-2 }\]
OpenStudy (anonymous):
Common denominator is ....?
OpenStudy (anonymous):
Ahhhhh dang...you're right.
OpenStudy (anonymous):
Hey, I'm waiting to see your multiplication ;)
OpenStudy (anonymous):
It didn't work so I have no idea.
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OpenStudy (anonymous):
I thought of making both denominators equal but I can't x_x
OpenStudy (anonymous):
Show me so I can know where to fix it?
OpenStudy (anonymous):
\[\frac{ 6a }{ 2a + 6 } - \frac{ -3a+ 12 }{ 3a + 6 }\]
OpenStudy (anonymous):
Ahhh!!! sorry, on the right, they're negatives.
OpenStudy (anonymous):
Common denominator is product of (a +3) ( a-2):
-> 3a ( a -2 ) = ....
-> (a - 4) ( a +3) = ...
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OpenStudy (anonymous):
Just follow me, work step by step fill out the blank!
OpenStudy (anonymous):
Haha, I'll try.
OpenStudy (anonymous):
Please post here!
OpenStudy (anonymous):
Post what?
OpenStudy (anonymous):
-> 3a ( a -2 ) = .... ?
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OpenStudy (anonymous):
\[3a ^{2} - 6a\]
OpenStudy (anonymous):
So it's just cross multiply?
OpenStudy (anonymous):
Great :)
-> (a - 4) ( a +3) = ... ?
OpenStudy (anonymous):
Exactly right :)
OpenStudy (anonymous):
\[a ^{2} -12\]
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OpenStudy (anonymous):
ahh
OpenStudy (anonymous):
I forgot some!!!
OpenStudy (anonymous):
FOIL method!
OpenStudy (anonymous):
\[a ^{2} -4a + 3a\] -12
OpenStudy (anonymous):
-> (a - 4) ( a +3) = a² -4a + 3a - 12 = ...
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OpenStudy (anonymous):
Can you simplify -4a + 3a = ....?
OpenStudy (anonymous):
-a
OpenStudy (anonymous):
So the answer is....
OpenStudy (anonymous):
-> (a - 4) ( a +3) = a² -a - 12
OpenStudy (anonymous):
\[\frac{ 2a ^{2} -7a -12 }{ (a+3) (a-2) }\]
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OpenStudy (anonymous):
Now after cross product, subtract the numerators:
3a²- 6a - (a² -a - 12) = 2a² -6a +a +12 = ...
OpenStudy (anonymous):
So I'm right?
OpenStudy (anonymous):
-6a + a = ....?
OpenStudy (anonymous):
Well the answer on the problem says 7a
OpenStudy (anonymous):
I don't see how they get 7a, probably typo :)
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OpenStudy (anonymous):
Maybe.
OpenStudy (anonymous):
I have 3 more and I tried one this way and it doesn't work.
OpenStudy (anonymous):
In short, learn how to subtract unlike fraction by cross product!
OpenStudy (anonymous):
Open the new posts for new questions!
OpenStudy (anonymous):
Make sure your post is correct!