Question

f(x)=ln(|-4x-46|); find points of discontinuance and state type of discontinuity
;jump,infinite,removed,or none

Answer 1

when is ln undefined?

Answer 2

when ln is < or = to 0?

Answer 3

yes exactly, when the argument (the bit inside) is less or equal to zero

(in fact it is defined for negative numbers, but it doesn't take real values; if you're interested then read about complex numbers)

so we should look at when |-4x-46| =< 0 then shouldn't we? what do you think?

Answer 4

yes so if i plug in -46/4 it would result in 0; undefined in ln. right?

Answer 5

yes :)

Answer 6

so since we're working with absolute values negative numbers would exist also. right?