a tugboat goes 180 miles upstream in 15hrs. the return trip downstream takes 5hrs. Find the speed of the tugboat w/o a current and the speed of the current.
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OpenStudy (lgbasallote):
upstream speed is given as
u = b - c
downstream speed is given as
d = b + c
where u = upstream speed
b = speed of boat
c = speed of curent
d = downstream speed
do you follow so far?
OpenStudy (anonymous):
i follow. what do I do next ?
OpenStudy (lgbasallote):
now.. can you identify what the upstream speed is?
OpenStudy (anonymous):
yes, the upstream speed is 12mph right ?
OpenStudy (lgbasallote):
yes right
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OpenStudy (lgbasallote):
how about downstream speed?
OpenStudy (anonymous):
the downstream speed is 36mph right ?
OpenStudy (lgbasallote):
right again.
OpenStudy (lgbasallote):
so you have
12 = b - c
an
26 = b + c
are you familiar with systems of linear equations?
OpenStudy (anonymous):
sort of
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OpenStudy (lgbasallote):
do you know the elimination method?
OpenStudy (anonymous):
yes. I think the answer is 24. Is that correct ?
OpenStudy (lgbasallote):
yes! speed of boat = 24
OpenStudy (lgbasallote):
now find speed of current
OpenStudy (anonymous):
how ?
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OpenStudy (lgbasallote):
rememeber:
d = b + c
you have the value of downstream speed and the speed of the boat
OpenStudy (anonymous):
ok, so the speed of the boat is 24 which makes the speed of the current 12 right ?
OpenStudy (lgbasallote):
right
OpenStudy (lgbasallote):
so there's your answer
b = 24 mph
c = 12 mph
OpenStudy (anonymous):
ok, thanks
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