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Factor: (x^2-4)(x^2+4)
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hint: \(x^2 - 4\) is difference of two squares the formula for difference of two squares is \[\huge a^2 - b^2 \implies (a+b)(a-b)\] does that help? or do you need more help?
so would it be: (x-2)(x+2)???
that's just for one x^2 - 4 remember: you have TWO
Yeah i am lost now hah
here's a hint: \[x^2 + 4 = (x-2i)(x+2i)\] does that help?
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nope you lost me, whats the i for?
it's an imaginary number
don't you have that?
if you haven't discussed it yet, you can just express it as \[(x+2)(x-2)(x^2 + 4)\]
Nope havent gottent that hah, but thanks for the help! Appreciate it!
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