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solve and check. 2log (x-1) = 2 + log 100 please help, i don't know what to do first... ?
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first, you put log 100 on the left side
mhm.. then?
what did you get?
2log(x-1) - log100=2 right?
right. simplify it
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okay.. uhmm.. so this is really new to me.. what do i do with the 2 in front of the log ?? :S
here are the rules you might want to learn POWER RULE: \[\huge \log_a b^c \implies c\log_a b\] PRODUCT RULE \[\huge \log_a (bc) \implies \log_a b + \log_a c\] QUOTIENT RULE: \[\huge \log_a (\frac bc) \implies \log_a b - \log_a c\] does that help?
yes , thank you... my unit notes did not give me those rules.. /:
no wonder. so now...simplify
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