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Mathematics 6 Online
OpenStudy (anonymous):

(x+1/x)-(x/x+1)=0

OpenStudy (anonymous):

Rewrite and cross multiply

OpenStudy (anonymous):

Could we instead find a common denominator for them?

OpenStudy (anonymous):

That's complicated, just (x+1/x)=(x/x+1) and cross multiply, very simple then

OpenStudy (anonymous):

Okay, I did that and got to \[x^{2}+2x +1=x^{2}\]

OpenStudy (anonymous):

What do I now do?

OpenStudy (anonymous):

Cancel the x^2

OpenStudy (anonymous):

U don't know that?

OpenStudy (anonymous):

I guess not.

OpenStudy (anonymous):

So then I have 2x+1=0 ... What now?

OpenStudy (anonymous):

If you don't know how to do that, I think you better go back to the beginning of your studies...

OpenStudy (anonymous):

What number when u double it and add 1 gives zero?

OpenStudy (anonymous):

-2

OpenStudy (anonymous):

No... I'm not sure.

OpenStudy (anonymous):

Like I said, back to basics for u....

OpenStudy (anonymous):

Let's not be rude. I'm here for help, and help is what I'm looking for. I never asked that my ability (or lack thereof) be called out.

OpenStudy (anonymous):

If you can provide assistance, please do so.

OpenStudy (anonymous):

You should not even need the amount of help I already gave you. I am not being rude, if you just want an answer, maybe someone else will give it to you.

OpenStudy (anonymous):

And on what standard are you basing my need for help? Help is help, regardless of the level at which it is required.

OpenStudy (zzr0ck3r):

2x+1 = 0 subtract 1 from both sides and what do you get?

OpenStudy (anonymous):

2x=-1

OpenStudy (zzr0ck3r):

devide by 2 on both sides and tell me what you get.

OpenStudy (anonymous):

x= -1/2

OpenStudy (zzr0ck3r):

correct

OpenStudy (anonymous):

Awesome! Thanks!

OpenStudy (anonymous):

Thank you estudier as well, for what help you did provide.

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