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OpenStudy (anonymous):
how do i find the exact value of ln e?
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OpenStudy (dumbcow):
take 2 and subtract 1 .... no since ln is log base e , they cancel each other leaving the exponent of 1
OpenStudy (dumbcow):
\[\ln (e^{n}) = n\] and \[e^{\ln (n)} = n\]
OpenStudy (anonymous):
awesome thanks
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