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Mathematics 18 Online
OpenStudy (anonymous):

how do i find the exact value of ln e?

OpenStudy (dumbcow):

take 2 and subtract 1 .... no since ln is log base e , they cancel each other leaving the exponent of 1

OpenStudy (dumbcow):

\[\ln (e^{n}) = n\] and \[e^{\ln (n)} = n\]

OpenStudy (anonymous):

awesome thanks

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