Need your help some.In 1980, median family was about $18,000, and in 2000 it was about $41,000. find the slope of the passing line (1980,18000) and (2000,41000) M= then interpret the slope as a rate of change lastly the median family income in 2006 will be $

Question

blues · Answer

M is the rate of change. It is the ratio of change in dollars to change in time.

So the change in dollars is 41,000 - 18,000. The change in time is 2000 - 1980.

The rate of change = change in dollars / change in time.

M = (41,000 - 18,000) / (2000 - 1980).

Have I made that clear enough?

anonymous · Answer

I got that m=1150 but I cant get the family income for 2006

blues · Answer

I agree with m. It is equal to 1150.

In order to predict income in 2006, you need to write out the equation of a line. Specifically:

median income = 1150 x year + intercept.

The intercept is what the median income was when year = 0.

If that is clear, I'll show you how to find the intercept from the info you have been given....

anonymous · Answer

ok so 
2006=1150x +?
I'm lost

blues · Answer

So when you are trying to find the intercept, you have one unknown variable. 

It tells you that in 1980, the median income was 18,000. So you put those two values into the formula you have:

median income = 1150 x year + intercept
18,000 = 1150 x 1980 + intercept

And then you solve for the intercept:

18,000 = 2277000 + intercept
-2259000 = intercept

Is the math for finding the intercept clear?

blues · Answer

You might want to write out my math on a piece of paper and work through the computation yourself. :)

anonymous · Answer

ok