Anyone to walk me through? The perimeter of a rectangle is 38 ft. The length is 3 ft longer than the width. Find the dimensions. Write a system of linear equations and solve the resulting system. Let x be the length and y be the width. Write the first equation. 2x+2y= Write the second equation. X=y+ What is the length? ( _) ft What is the width? ( ) ft
ok
so the first equation is the perimeter...
|dw:1347245725455:dw|
2W+2L = perimeter
the second equation asks about the relationship between L and W
that's talked about in the problem...
so the perimeter states it is 38ft (2w+2L)
L= W+ ?
yes
Length= x, width=y, length longer than width means x=3+y perimeter = x+x+y+y , which is sum of all sides, using x=3+y in this equation perimeter = 6+y+y+y+y p=6+4y
Ok so L=W+38? (Algebraic)?
I am not paying attention to that person, I want to learn. If you're still willing to help me. :)
well if you say length = x or L , then we need to understand length is 3 more than width which is say Y or W
Confused.....
please let me know where are you confused
so L=W+38? got that far...
I am sry, but L is not equal to w+38
lets say Length = L and widht = w
we know length = 3 more than width, right ? so L=3+W
Perimeter is sum of all sides = length+length+width+width
we have Perimeter =38 , 38=L+L+W+W, BUT WE KNOW that L=3+W , so put that in the former equation 38=3+W+3+W+W+W, we have 38= 6+4W
does that help
12.5? length and 9.5 for width. Is this correct?
let meknow if there is reason for confusion
I divided the perimeter by 4... 38/4 which gave me 9.5 then I added 3 to that which gave me 12.5 (because it 3 more than) Am I figuring this incorrectly?
no no, we cant divide, we have to move 4 to left side of equation, take away 4 from 38
I really have no idea what I am doing. Sigh.
4 from 38 is 34
I think everyone gave up on helping me. ....
oops there was a typo, take away 6 from 38 and we get 32 32=4w, solve for w and w=8
so w=8 l=11
great
thank you.
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