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-6<2x-6<= to 8
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add 6 all the way across, then divide by 2
huh? isnt the 6 going to cancel out how would i show my work
yes, that is the point, the 6 will "cancel" aka add up to zero so you can get \(x\) by itself
don't be confused by the fact that you will get 0 on the left. 0 is a perfectly good number first step will get you \[0<2x\leq 14\]
can you write it out for me im still a lil lost
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then divide by 2
\[-6<2x-6\leq 8\] add 6 \[0<2x\leq 14\]divide by 2\[0<x\leq 7\]
so im adding the 6,s underneath the 6;s
the 6's cancled out and became 0 right
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