Question

SOMEBODY PLZ HELP ME ON THIS??

Bill Palow invested 30,000 for one year in two separate accounts paying 3% and 4.1% annual simple interest. If Bill earned a total of 1091.73 from the two investments, how much was invested in each account?

Answer 1

I=PRn

let R1=0.03
let R2=0.041

Invested amount = 30000 = a+b

I=1091.73=1(0.03a + 0.041b)
a = 30000-b

Sub
1091.73=0.03(30000-b)+0.041b

Answer 2

Find b and then sub to find a

Answer 3

I know I have terrible setting out

Answer 4

THE N IN THE EQUATION STANDS FOR NUMBER OF YEARS RIGHT?

Answer 5

Yes

Answer 6

SO THE PRINCIPAL EQUALS 3OOOO?

Answer 7

P=a+b

Answer 8

OH

Answer 9

SO THEN I EQUALS 30000

Answer 10

P= invested amount
I = interest, which is amount that is earned
n = number of years
R = rate of interest per annum

So yes P =30000

Answer 11

THNK YOU