Question

Find the x and y intercepts and then sketch the graph for:
y=x^2 + 6x + 9

Answer 1

what do u do for finding the intercepts on x and y axis?

Answer 2

suppose u have to sketch 2x+3y=6

Answer 3

find out, where the curve y=x^2 + 6x + 9 will cut the axes?

Answer 4

yes i did this too find the x intercept but it doesn't make sense:
y=(x+3)(x+3) <------ factorised
let y = 0
x+3= 0
x=-3

but then both x intercepts = -3. that doesnt make sense

Answer 5

for x intercept...put y=0 then x=-3
for y intercept ...put x=0 then y=9

Answer 6

but then both x intercepts = -3. that doesnt make sense???

Answer 7

there should be two different x intercept but they both =-3.

Answer 8

u have to sketch y=(x+3)^2
It'll cut the axes at (-3,0) and (0,9)

Answer 9

its a parabola

Answer 10

for x intercept, we put y=0
so (x+3)(x+3)=0

Answer 11

then we get a repeated root x=-3...and it'll cut the x-axis once only

Answer 12

it makes sense that this graph only has 1 x-intercept, because it touches x-axis only at a point (-3,0) , that is x axis is tangent to this graph.....