The number of viewers of a weekly TV newsmagazine show, introduced in the 2003 season, has been increasing (in million viewers/year during its t year on the air) at the rate given below.
2(5 + 1/2 t)^(-1\/3) (1

Question

The number of viewers of a weekly TV newsmagazine show, introduced in the 2003 season, has been increasing (in million viewers/year during its t year on the air) at the rate given below.
2(5 + 1/2 t)^(-1\/3)   (1<=t<=6\)
The number of viewers of the program during its first year (t = 1) on the air is given by 6(11/2)^(2/3) million. Find how many viewers were expected in the 2006 (t = 4) season. (Round your answer to one decimal place.)
________ million viewers

anonymous · Answer

Might as well simplify all that first.

anonymous · Answer

For example, "6(11/2)^(2/3) million" = 18,695,039