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What is the standard form equation of the line passing through (3, –2) with a slope of ?
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The question is incomplete. You either need the slope or another point.
The slope is 3/5
y - y1 = m*(x-x1) m is slope
^ I know this
plug in the values then
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I did. 5x – 3y = 19 5x – 3y = –19 3x – 5y = 19 3x – 5y = –19 The answer choices aren't what I am getting!
show me how u solved it
y-y1=m(x-x1) plug in the values y+2=3/5(x-3) don't know where to go from there
y+2=3/5(x-3) 5(y+2)=3(x-3) 5y + 10 = 3x - 9 10+ 9 = 3x - 5y 3x - 5y = 19 C
Thanks!
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