How do you find the substitution for these? 2x + y = 7 y - x = 1
solve the second equation for y and then plug into the first one
do yo know how to add equations yet?
Solve The Second Equation For Y And Then Plug Into The First One
I kind of know how to add them, but the set up of it being in two is confusing.
y-x=1 find y in that equation. Then plug y into the top equation and then find x.
basically when doing substitution you want to solve one equation for one variable (either x or y in this case) and then plug it into the equation you did not use
Y-x=1 Find Y In That Equation. Then Plug Y Into The Top Equation And Then Find X
Why is damn just restated things people have already said? lol
well before I continue on, the question given is : Which of the following would not be the result of a substitution in the following system? these are the options: 7 - 2x - x = 1 2x + x + 1 = 7 2(y + 1) + y = 7
restating*
try doing the suggested manipulation stated above and then see what you get..
What do you mean?
Ill work it out for you... (1) 2x+y=7 (2) y-x=1 Solving (2) for y yields: y=x+1--- we can call this (3) now plugging (3) into (1) : 2x+(x+1)=7
2x+4=7?? and you didn't have to work it out, but thank you for doing so.
Ooops, I misread, that was the answer at the bottom. Thank you for the help, I now know how to set it.
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