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Mathematics 13 Online
OpenStudy (anonymous):

How do I solve this problem -7(the lesser than or equal to sign) 2x+3(<) 5

OpenStudy (anonymous):

you are going to need to set up two equations

OpenStudy (anonymous):

one -7(less than or equal sign) 2X+3 two 2X+3(<)5 you will get two answers it would look like this for example 6<x>9

OpenStudy (anonymous):

Alright Thank you, I will tell you what I came up with so far

OpenStudy (anonymous):

k

OpenStudy (anonymous):

for my solutions I have(-5,infinity symbol] and (5/2,infinity symbol)

OpenStudy (anonymous):

Infinity?

OpenStudy (anonymous):

ok lets work Equation one -7(Less than or equal) 2X+3

OpenStudy (anonymous):

subtract 3 from both sides

OpenStudy (anonymous):

I end up with 2 is less than or equla to x

OpenStudy (anonymous):

you should get -10 since you subtracted -3 and you have a -7 on the other side you get -10

OpenStudy (anonymous):

alright

OpenStudy (anonymous):

-7 (less than equal) 2X+3 -3 -3 =-10 (less than equal) 2x

OpenStudy (anonymous):

then divide by 2 and we get -5

OpenStudy (anonymous):

yup good job!

OpenStudy (anonymous):

do the same for the other equation

OpenStudy (anonymous):

but I am supposed to express each in interval notation

OpenStudy (anonymous):

and for the other equation x<5/2

OpenStudy (anonymous):

you should get 1 for the other equation

OpenStudy (anonymous):

2X+3<5 -3<-3 2X<2 divide by 2 on both side 2 2 X=1

OpenStudy (anonymous):

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