Question

determine whether the equation defines y as a function of x. 6x^2+y^2=1. can someone help me out real quick with this one

Answer 1

someone help me please

Answer 2

help help !!

Answer 3

is y^2 = x a function?

Answer 4

it says determine whether the equation defines y as a function of x for
6x^2+y^2=1

Answer 5

yes I know, but the question I asked has the same answer.

so

is y^2 = x a function of x?

Answer 6

please show work for this one

Answer 7

if you solve for y you get y = +-sqrt(x) correct?

Answer 8

im lost please just work this one for me and i will figure this out

Answer 9

6x^2+y^2=1 first solve for y

y^2 = 1-6x^2

y = +- sqrt(1-6x^2) correct?

Answer 10

yes

Answer 11

next

Answer 12

so yes right?

Answer 13

so what is a function? it cant have two different y values for any x, so.

in your clase if you put in, lets say x = 2 you will get two different answer

mainly, -sqrt(1-6x^2) and sqrt(1-6x^2)

so is it a function then?

Answer 14

no?

Answer 15

correct, but you need to understand why, do you?

Answer 16

because got 2 different answers

Answer 17

right