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Mathematics 17 Online
OpenStudy (anonymous):

(needs to set up equation!) Tasha bought salads at $2.75 each and cartons of milk at $.80 each. The total cost was $16.15. how many of each did Tasha buy?

OpenStudy (anonymous):

Salads are S and milk cartons are M. She bought S salads at 2.75 per salad, spending 2.75S on salads. She bought M milk cartons at .80 per carton, spending .80M on milk. She spent a total of 2.75S+.80M and we are told that the total cost is 16.15. Our final equation is 2.75S+.80M=16.15.

OpenStudy (anonymous):

i need help to solve too please!

OpenStudy (anonymous):

@malexj93 are you there?

OpenStudy (anonymous):

S and M are natural numbers. The total cost ends in 5, so S must be odd since an even S would have a 0 at the end and all M have a 0 at the end. Odd S end in either 25 or 75, and we need to end in 15. All M end in E0, where E is an even number. We need S that end in 75, because 25+E0 will be E5, not necessarily the same E though. To get S cost to end in 75 we need to make S 1,5,9,... every other odd number. We know 9 is too big because 9(2.75) is more than 16.15, so we try 1 and 5 and see which will result in a possible natural number value for M.

OpenStudy (anonymous):

but i need to solve the equation?

OpenStudy (anonymous):

dont you need to set the equation up?

OpenStudy (anonymous):

2.75S+.80M=16.15 This was the equation. The method I gave was to solve it.

OpenStudy (anonymous):

but how can we solve it like what do we cancel out thats what im confused about and what do we plug in. we need to get s by itself or m by itself right?

OpenStudy (anonymous):

What class are you doing this in?

OpenStudy (anonymous):

Algebra 1

OpenStudy (anonymous):

Okay, well then that method might be a bit advanced. We could solve for one of the variables but unless we know the value of the other variable it won't help.

OpenStudy (anonymous):

yes that's what i need to do but i dont know how to do it and i need help

OpenStudy (anonymous):

We need to recognize that S and M can only be natural numbers i.e. 1, 2, 3, etc. She can't buy 1.5 cartons of milk, right?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

So we can solve for M and try values of S such as 0, 1, 2, 3 that give us an M that isn't a decimal.

OpenStudy (anonymous):

ok but how do we know which number is the right number to pick

OpenStudy (anonymous):

2.75S+.80M=16.15 2.75S=16.15-.80M S=(16.15-.80M)/2.75

OpenStudy (anonymous):

how do i do that?

OpenStudy (anonymous):

what do i plug in into the s or m

OpenStudy (anonymous):

I solved for S, but you could solve for either one. In my case, I would pick numbers for M, starting with 0, then trying 1, 2, 3, 4, etc. When I plug in 0 it gives me a decimal for S. This can't be right because she can't buy a decimal amount of salads. That means we need to try 1. We repeat the process until we find an S that doesn't have a decimal or fraction.

OpenStudy (anonymous):

s=5 ,m=3 ?

OpenStudy (anonymous):

yes, perfect!

OpenStudy (anonymous):

i did it so the trick is to try out random numbers startng from zero if you dont have values for one particular variable?

OpenStudy (anonymous):

yeah, it works in word problems mostly because you have the limitation that they have to be whole numbers. Otherwise, they'll give you one value and ask you to find the other.

OpenStudy (anonymous):

ok thank you! can you mind helping me in one last problem please?

OpenStudy (anonymous):

Sure, what is it?

OpenStudy (anonymous):

A rectangular garden is 45 feeet long and has perimeter of 150 feet. Rows of plants are planted 3 feet apart. Find the area of the garden.

OpenStudy (anonymous):

First, is there any information here that seems useless?

OpenStudy (anonymous):

45 feet long?

OpenStudy (anonymous):

That's useful, the perimeter and the area both depend on length.

OpenStudy (anonymous):

oh im not sure? the plants are planted 3ft apart?

OpenStudy (anonymous):

yes, the plant spacing.

OpenStudy (anonymous):

We don't know for sure that it will be useless, but it's definitely not something that perimeter and area depend on.

OpenStudy (anonymous):

ok but how would we set this equation up to find the area?

OpenStudy (anonymous):

We know that P=2L+2W and A=LW.

OpenStudy (anonymous):

We know L and P, so if we plug them into Equation 1 we can solve for W. Once we know W, we can plug L and W into Equation 2 and get Area.

OpenStudy (anonymous):

ok can you give me a minute to solve please

OpenStudy (anonymous):

yup, take your time.

OpenStudy (anonymous):

the area is 1350?

OpenStudy (anonymous):

Perfect!

OpenStudy (anonymous):

thank you so so much you're such a great help!

OpenStudy (anonymous):

It's my pleasure :) I'm going now, you have a good day!

OpenStudy (anonymous):

you too :)

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