Question

Limit as x->(pi/2) of [tanx + 1/(x-pi/2)]? Anyone?

Answer 1

do you get zero over zero?

Answer 2

i think you are supposed to recognize this as the derivative of tangent, evaluated at \(\frac{\pi}{4}\)

Answer 3

oops rather \(\frac{\pi}{2}\)

Answer 4

derivative of tangent is secant squared, and secant square of \(\frac{\pi}{2}\) is your answer