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Solve for x: logbase4((x/2) + 4) = 3 Can someone explain this to me?
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\[ \large \log_4(x/2+4)=3 \]
right
use this \[ \large \log_ab=y\Leftrightarrow a^y=x \]
4^3 = (x/2 + 4)?
yes
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yes
why do you do that?
now add -4 to both sides
do what?
what is "log", I can't remember
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log = logarithm
x = 120
what is a logarithm
yes. x=120
http://www.wolframalpha.com/input/?i=logarithm&a=*C.logarithm-_*MathWorld-
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I remember what a logarithm is now. It's weird, I've forgotten a lot of stuff since last year. That inverse question you answered for me a minute ago would've been a breeze before. I don't know why I forget
when u don't practice, u forget. the same happens to me with several var. calc.
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