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A telephone line hangs between two poles 14 m apart in the shape of the catenary y = 20cosh(x/20) - 15, where x and y are measured in meters. (Diagram: http://i.imgur.com/BCePs.gif) (a) Find the slope of this curve where it meets the right pole: The slope is sinh(7/20) (b) Find the angle θ between the line and the pole: θ = 90° - α, so my question is, why is there an angle α and where is it located?
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hmm i am not great with hyperbolic functions but wouldn't the angle theta be described as \[\tan \theta = \sinh(7/20)\] \[\theta = \tan^{-1} [\sinh(7/20)]\]
oh wait....i just described alpha not theta lol
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