Question

what are two numbers whose difference is 48 and their quotient is 7? how do you do this

Answer 1

two numbers whose difference is 48 so

x - y = 48

quotient is 7 so

x/y = 7

does that help?

Answer 2

so am i trying to find two numbers that subtract and equal 48 and the same two numbers divide and equal 7

Answer 3

yep

Answer 4

is that even possible 7 doesn't even go into 48

Answer 5

it is possible..

Answer 6

there may be a chance the numbers are fractions though

Answer 7

you should use algebra to be sure

Answer 8

ive been trying i cant figure it out it is very frustrating

Answer 9

okay..i gave you

x/y = 7

can you rewrite this equation so that it shows x = ?

Answer 10

what?

Answer 11

do you get how i got

x - y = 48

and

x/y = 7?

Answer 12

yes i get that, i don't understand how two numbers subtract = 48 and those same two numbers divided = 7 i have subtracted many numbers that = 48 but when you divide them they don't = 7

Answer 13

stop trying trial and error...this is solveable by algebra

Answer 14

so you have

x/y = 7

do you know how to express this in terms of x?

Answer 15

no

Answer 16

do you know how to cross multiply?

Answer 17

48 x 7

Answer 18

no... at x/y = 7

Answer 19

\[\huge \frac xy = 7\]
cross multiply

Answer 20

i have no idea

Answer 21

multiply y to 7 what do you get?

Answer 22

7y

Answer 23

right so x = 7y

Answer 24

now substitute x = 7y into

x - y = 48

Answer 25

x-7y=48

Answer 26

no... 7y - y = 48

x = 7y so you substitute 7y into x

does that make snese?

Answer 27

ok so 6y = 48

Answer 28

right. now solve for y

Answer 29

y=8?

Answer 30

yes

Answer 31

so now solve for x

x - 8 = 48

Answer 32

x=56

Answer 33

right

Answer 34

so there are your numbers.. 56 and 8

Answer 35

anyway...i need to go now so good luck

Answer 36

i am jumping up and down cheering for myself thank you so much

Answer 37

welcome