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OpenStudy (turingtest):
distribute a and c
what do you get?
OpenStudy (anonymous):
3txc-2bc=dcx-2c?
OpenStudy (turingtest):
how did you get a c on the left?
OpenStudy (turingtest):
you have an a on the left and a c on the right...
OpenStudy (anonymous):
didn't meant to press that........ 3tx-2bc=dcx-2c <--- meant that
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OpenStudy (turingtest):
there is still no a on the left, and there is still a c
just simplify the left:
a(3tx-2b)=?
OpenStudy (anonymous):
3txa-2ab
Directrix (directrix):
3txa-2ab = c(dx-2)
What does c(dx-2) equal when the "c" is distributed over the (dx-2)?
OpenStudy (anonymous):
dxc-2c
Directrix (directrix):
3txa-2ab = c(dx-2)
3txa -2ab = cdx -2c
Get the terms containing x together on one side of the equation and the terms not containing x on the other side.
3txa - cdx = 2ab - 2c
(3ta)x - (cd) x = 2ab - 2c
Check that.
Then, factor x from the left side to get:
x [ 3at - cd ] = 2ab - 2c
Then, what do you think should happen next?
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