a(3tx-2b)=c(dx-2) find x
distribute a and c what do you get?
3txc-2bc=dcx-2c?
how did you get a c on the left?
you have an a on the left and a c on the right...
didn't meant to press that........ 3tx-2bc=dcx-2c <--- meant that
there is still no a on the left, and there is still a c just simplify the left: a(3tx-2b)=?
3txa-2ab
3txa-2ab = c(dx-2) What does c(dx-2) equal when the "c" is distributed over the (dx-2)?
dxc-2c
3txa-2ab = c(dx-2) 3txa -2ab = cdx -2c Get the terms containing x together on one side of the equation and the terms not containing x on the other side. 3txa - cdx = 2ab - 2c (3ta)x - (cd) x = 2ab - 2c Check that. Then, factor x from the left side to get: x [ 3at - cd ] = 2ab - 2c Then, what do you think should happen next?
divide both sides by 3at-cd so x is left alone
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