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Find x in [−6π, 0] such that cos(x/6) = 1/2
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\[cos\left(\frac{x}{6}\right) =\frac{1}{2}\] well have you tried it yet
yes. it doesnt work
what have you tried
i tried doing cos^-1(1/2) and multiplying by 6
do you know general solutions?
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no haha
\[\cos\left(\frac{x}{6}\right) =\frac{1}{2} => \frac{x}{6} =\cos^{-1}\left(\frac{1}{2}\right) => \frac{x}{6} =\frac{\pi}{3} \]
are you able to do it now
no that didnt work :( but i feel like thats almost right. How did you know it equaled pi/3?
\[\frac{x}{6} =\frac{\pi}{3} => 3x = 6\pi => x= 2\pi \] it works
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i didnt accept it lol
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