last question. . three numbers form an arithmetic progression having a common difference of 4. If the first number is increased by 2, the second number by 3, and the third number by 5, the resulting numbers form a geometric progression. Find the original numbers.
ok let suppose originl numbers are d , d+4 , d+8
is that right?
second parts says d+2 , d+7 , d+13 are in GP
how about this one?
i dont really understand that problem
ok lets see other opinions :)
It would have been nice to chose a rather than d then mukushla
*there
Also, let the numbers be: a-4,a , a+4
i just realized that before posting my first reply
Now in the Second case we have: a-2, a+3, a+9
the no. r 23, 27,31
Correct mukushla?
Note: I took original no. as: a-4, a, a+4
got it @babybaby ?
thank you again and again and again
You're most welcome.
this site answered my math problems.
nice to hear : \[\huge{\color{blue}{\frak{Welcome}} \space \color{red}{\mathbb{To}} \space \color{green}{\textbf{Open Study}}}\]
\[\huge \color{blue}{\boxed{\color{red}{\cancel{\color{black}{\color{green}{\text{MATH}}}}}}}\]
Join our real-time social learning platform and learn together with your friends!