Question

How do I find the delta of

lim x^3=8
x->2
for an epsilon=0.001

Answer 1

what does epsilon represent

Answer 2

what does; epsilon, delta represent

Answer 3

\[\lim\limits_{x\rightarrow 2}x^3=8\]\[\epsilon =0.001\]\[\delta=?\]

Answer 4

I know that I have to do

\[\left| x-8 \right|>\epsilon\] if \[0>\left| x-2 \right|>\delta \]

Answer 5

how can the absolute value of something be less than zero?

Answer 6

\[0<|x−2|<δ
\]

Answer 7

u have \[|x^3-8|<\epsilon=0.001\]and u want to find delta with \[|x-2|<\delta\]which implies that delta

Answer 8

sorry
*implies that epsilon

Answer 9

hint \[-0.001+8<x^3<0.001+8\]apply \(\sqrt[3]{}\)