Solve the triangle.

a = 12, b = 21, C = 94°

choices:
c ≈ 24.2, A ≈ 32.7°, B ≈ 53.3°

c ≈ 24.9, A ≈ 54.3°, B ≈ 31.7°

c ≈ 24.2, A ≈ 28.7°, B ≈ 57.3°

c ≈ 24.9, A ≈ 28.7°, B ≈ 57.3°

Question

Solve the triangle. 

a = 12, b = 21, C = 94°

choices:
 c ≈ 24.2, A ≈ 32.7°, B ≈ 53.3°

 c ≈ 24.9, A ≈ 54.3°, B ≈ 31.7°

 c ≈ 24.2, A ≈ 28.7°, B ≈ 57.3°

 c ≈ 24.9, A ≈ 28.7°, B ≈ 57.3°

anonymous · Answer

Do you know the law of cosines? You can try that to find the first value. After that, just use the law of sines to complete the rest.

anonymous · Answer

can you show me step by step?

anonymous · Answer

$$c^2=a^2+b^2-2abcos(C)$$
you are given a, b, and C, solve for c

anonymous · Answer

im confused... @J_Liu

anonymous · Answer

Given the values of a, b and C, you can calculate $$c^2$$ = value and take the square root.

anonymous · Answer

$$c^2 = 12^2 + 21^2 - 2(12)(21)\cos(94)$$