Question

physics

Answer 1

When the acceleration is constant, we may use the formula

\(\large v = v_0+at\)

Where: \(v = \text{Final Velocity}, \\v_0= \text{Inital Velocity}\\a= \text{Acceleration
}\\t=\text{Time interval}\)

In this question, \(v = 13.8m/s\\v_0=6.9m/s\\a=4.35m/s^2\), we are looking for time interval in which the car will accelerate from 6.9m/s to 13.8m/s, you'll get the constant \(t\), which represents the elapsed time in seconds.

Answer 2

We know that the displacement \(\large \Delta x = x-x_0\), where \(x_0=\text{Initial position coordinates}\\x = \text{Final position coordinates}\)

is given by \(\large x = x_0+\frac{1}{2}(v_0+v)t.\)