solve by factoring: 8x^2+6x-2=0
so far i have simplified it to:
2(x+1)(4x-1)=0
how do i solve the rest of this?

Question

solve by factoring: 8x^2+6x-2=0
so far i have simplified it to:
2(x+1)(4x-1)=0
how do i solve the rest of this?

anonymous · Answer

I'll take your word for it, looks pretty well factored to me..:-)

anonymous · Answer

i just do not know how to solve for x with the 2 in the front

anonymous · Answer

You could divide both sides by 2

anonymous · Answer

ok.  i know that you have to separate each part that is in parenthesis and then set the two parts each equal to zero.  so can i take the first part...2(x+1)...and set that whole part equal to zero?

anonymous · Answer

yes, and then you can get rid of the 2 by doing what estudier said to do. divide both sides by 2.

anonymous · Answer

oh ok thank you