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solve by factoring: 8x^2+6x-2=0 so far i have simplified it to: 2(x+1)(4x-1)=0 how do i solve the rest of this?
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I'll take your word for it, looks pretty well factored to me..:-)
i just do not know how to solve for x with the 2 in the front
You could divide both sides by 2
ok. i know that you have to separate each part that is in parenthesis and then set the two parts each equal to zero. so can i take the first part...2(x+1)...and set that whole part equal to zero?
yes, and then you can get rid of the 2 by doing what estudier said to do. divide both sides by 2.
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oh ok thank you
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