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OpenStudy (anonymous):
What is the equation in standard form of the line which passes through (6, 3) and has a slope of ?
2x + 3y = 3
2x – 3y = 3
3x + 2y = 3
3x – 2y = 3
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OpenStudy (anonymous):
do you know what the standard form of a linear equation looks like?
OpenStudy (anonymous):
No
OpenStudy (anonymous):
y=mx+b m is the slope and b is the y intercept. so.. is your question incomplete or are u supposed to use the given equations to compute the slope?
OpenStudy (anonymous):
the slope is 2/3
jimthompson5910 (jim_thompson5910):
Hint:
In Ax + By = C
the slope is -A/B
In Ax - By = C
the slope is A/B
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OpenStudy (anonymous):
if you know the slope and the point it passes through you can use the point slope formula to figure out the equation of the line. y-y1 = m(x-x1)
OpenStudy (anonymous):
so y - 3 = 2/3(x - 6)
OpenStudy (anonymous):
can you solve from there and rearrange to the right form?
OpenStudy (anonymous):
I can't get the fraction part figured out
jimthompson5910 (jim_thompson5910):
Hint:
start with
y - 3 = 2/3(x - 6)
and multiply everything (but the stuff in the parenthesis) by 3 to get
3y - 9 = 2(x-6)
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OpenStudy (anonymous):
I got 2x-3y=3.
jimthompson5910 (jim_thompson5910):
you are correct
OpenStudy (anonymous):
Awesome. Thanks muchos
jimthompson5910 (jim_thompson5910):
yw
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