2m-29-8m=-35-28m-10, anybody plz?
solve for m?
first combine the like terms on each side of the equation
then move constant terms to one side and your variable terms to the other side.
so 2m - 8m - 10m?
well.. actually you would combine 2m - 8m on the one side.. and -35 - 10 on the other side.
so it would look like -29 - 6m = -45 -28m
with me?
your rit my bad
np, not your bad :) is why we are all here, for help. so you should get m = to a fraction of some sort. lemme know what u get or if you got it from here.
wouldnt 2m - 8m = -6?
no, you cannot get rid of the m term by subtracting. if m was 5 then would 2(5) - 8(5) = 6? no that would be like negative 30.
wait i think i see how it is, so if you get, for xample, -6 and 5 was in front of it u wud put down 5-6 and not 5 - (-6)? rit?
are yhu buyin what im sellin?
-6 +5 = 5-6 correct.. they both equal negative 1
so for this question -29 - 6m = -45 - 28m now, add 28m to both sides.. u get -29 + 22m = -45. now add 29 to both sides.. you get 22m = -16 right?
you have now have m on one side and the constant on the other. now isolate m by using division.
so its 22m/22 = -16/22 ?
yep, then reduce to m = -8/11
make sense?
wait how did yhu get -8/11?
hellooo...?
cause 22m / 22 = -16/22 right?
so \[m=\frac{ -16 }{ 22 }\] and if you reduce.. divide by 2 to numerator and denominator.. you get \[\frac{ -8 }{ 11 }\]
yes dats true thanks
great, hope it helped. let me know if you get stuck on another :)
but i dont need it simplifyed i need help to get to the answer to m what does -16/22 cuz i get a wierd answer.
helloooooo..
wait.. what? you need -16/22 in decimal form?
\[-\frac{ 16 }{ 22 }=-16\div22=-.72 repeating\]
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