sketch the solid described by the given inequalities (cylindrical coordinates) 0(

Question

sketch the solid described by the given inequalities (cylindrical coordinates) 0(<or=)(theta)(<or=)Pi/2 and            r(<or=)z(<or=)2. What would that look like?

turingtest · Answer

from theta to pi over two is in the first octant, right?

anonymous · Answer

yes

turingtest · Answer

I mean from 0*

turingtest · Answer

now r is the radius, so at the origin z=0 what is the radius?

anonymous · Answer

I would think 0

turingtest · Answer

right, so it's just a point
what about when z=2, what is the radius?

anonymous · Answer

2

anonymous · Answer

less than or equal to 2 I should say I guess

turingtest · Answer

right
in general, whatever our z<= whatever r is, and r^2=x^2+y^2|dw:1347500316259:dw|

turingtest · Answer

|dw:1347500358530:dw|

turingtest · Answer

|dw:1347500449667:dw|at z=1 the radius is 1 and sweeps out from 0 to pi/2 in octant one

turingtest · Answer

|dw:1347500525002:dw|at z=2, r=2, sweeping over the same area

turingtest · Answer

|dw:1347500595221:dw|imagining all the points in between you can imagine that the line from origin to the outer edges of a circle will be a straight line