Find the derivative of the function integral from 4x to 7x of (u^2-1)/(u^2+1)
\[\int\limits_{4x}^{7x} \frac{ u^2-1 }{ u^2 + 1 }\]
are u sure the problem like that ??
I'm suppose to find the derivative of that integral
yea i see.. but actually if using u's variables, so we use sign du.. but there i cant see du or dx ?
Yeah I have no idea how to approach this problem because u-substitution wouldn't apply
summon or tag @Hero , @hartnn ....
Is it du or dx?
du
Okay
Integral and Derivative are inverses of each other, so you end up with the the original function you came up with including the limits of integration: \[\left[ \frac{u^2-1}{u^2+1} \right]^{7x}_{4x}\]
Then continue evaluating: \[\left[ \frac{u^2-1}{u^2+1} \right]^{7x} - \left[ \frac{u^2-1}{u^2+1} \right]_{4x}\]
\[\left[ \frac{(7x)^2+1}{(7x)^2-1} \right] - \left[ \frac{(4x)^2+1}{(4x)^2-1} \right]\]
I'm pretty sure you can finish that on your own.
thank you
yw
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