Question

Hey is anyone familiar with 4 digit chopping arithmetic?

Answer 1

Doesn't sound familiar, but I might know what you mean by another name.

Answer 2

Like at what point do I chop?

Answer 3

Like you only have four digits after the decimal

Answer 4

Do I chop at the end or at every point that there is more than 4 digits after the decimal?

Answer 5

Do you mean rounding, truncating, or determining significant figures?

Answer 6

def not rounding

Answer 7

idk what the others r

Answer 8

Sounds like you mean truncating then. Truncate = chop off.

Answer 9

ohhhh lol
Ya like when do i chop off?

Answer 10

If you want your answer to only have 4 digits, then count four digits starting from the left, keep those four and get rid of all the rest.

Answer 11

Example. 123.456789 truncated to four digits = 123.4

If you want to truncate to a particular place value, say, the ten-thousandths place, then
123.4567 is truncated at the fourth digit after the decimal point.

Answer 12

yes but my question is as follows like do u chop off like at any point while u r solving or only once u have solved the whole equation?

Answer 13

Like do u contiously chop off?

Answer 14

Ah, only round or truncate at the very end of your calculations!
That is very important.

Answer 15

no, only after u finish solving

Answer 16

THANNNKKKSSSS lol

Answer 17

That is a matter of significant figures then. If you round or truncate in the middle of your calculations you'll get round-off error and all sorts of other nasty business.

Answer 18

ya i figured so i just had to dbl check

Answer 19

Check this example: 12.34567 times 2.98765 = 36.88454098...
Truncated at the fourth digit is 36.88
But if you 'chop' first then, 12.34 times 2.987 = 36.85958, which would be chopped to 36.85.
That is off from the correct answer by 3/100.

Answer 20

Thanks