I need A LOT of help with these two.

1. Suppose triangle ABC has vertices at A(1, 0), B(10, 0), and C(2, 6). After a 60° counterclockwise rotation about the origin, vertex A' has coordinates (0.50, ?).

2. Triangle PQR has vertices P(0, 1), Q(0, -4), and R(2, 5). After rotating triangle PQR counterclockwise about the origin 45º, the coordinates of P' to the nearest hundredth are (-0.71, ?).

Question

I need A LOT of help with these two. 

1. Suppose triangle ABC has vertices at A(1, 0), B(10, 0), and C(2, 6). After a 60° counterclockwise rotation about the origin, vertex A' has coordinates (0.50, ?).

2. Triangle PQR has vertices P(0, 1), Q(0, -4), and R(2, 5). After rotating triangle PQR counterclockwise about the origin 45º, the coordinates of P' to the nearest hundredth are (-0.71, ?).

anonymous · Answer

I know that the first answer is .87, but I have no idea how I got that.

anonymous · Answer

draw the triangle in xy-plane(rough sketch)