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simplify \[\frac{ 2x ^{-3} }{ -3y ^{-2} }\]
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do you know what is x^-3/x^-2
x^2/x^3?
\[\frac{x ^{A}}{x^{B}} = x^{A-B}\]
1/x
yeah. So now can you solve the problem?
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what about the different bases?
they're not different
my bad, I need to amend the question.
\[2x^{A} =/= (2x)^{A}\]
What's there to simplify ?
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you can't really simplify it, but there's one thing you can do: switching the place on the fraction and making the exponent positive
ok
what is the rule of that?
\[a/x = a * (1/x)\]
and 1/(1/x) = x
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a/(b/x) = ax/b
so if an exponent is negative, you just switch the place in the fraction and make the exponent positive
cheers.
np
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