Question

Find the inverse function: f(x) = 6 - 3/(x^(2)) , x > 0

Answer 1

y=6-3/x^2
Interchange x and y

Answer 2

What am I doing wrong here?
Here is my work so far:
X = 6 - 3 / y^(2)
x-6 = -3/y^(2)
-1/3x +2 = y^2)
(1/3x-2)^(1/2) = y

Answer 3

can u?

Answer 4

In step 3, I multiplied both sides by -1/3

Answer 5

u multiplied by -1/3 but i took y^2 in numerator ....

Answer 6

x-6 = -3/y^(2)
y^2=(-3)/(x-6)
y^2=-3/(x-6)

Answer 7

Got your mistake?

Answer 8

1 sec, let me look at what you wrote

Answer 9

I dont get how you went from step 1 to 2

Answer 10

x-6 = -3/y^(2)
(x-6)*(y^2)=-3

Answer 11

Do u understand it

Answer 12

Ah yes.

Answer 13

So now, you get y^(2) = -3 / x-6
y = square root(-3/x-6)

Answer 14

y=+- square root ((-3)/(x-6))

Answer 15

Just typed it on the website that I'm doing the homework on. The answer is correct :), tyvm

Answer 16

Since x>0 for f(x), negative sign is rejected

Answer 17

So it becomes y = square root(-3/x-6)

Answer 18

yeah :). Thank you :D