Question

\[\sqrt{x+3}+3=x\]

Answer 1

Subtract 3 from both sides.\[\sqrt{x + 3 } = x - 3\]Now, square both sides.\[x + 3 = (x - 3)^2\]Expand RHS, then solve for \(x\).

Answer 2

that method will work, and it is the best method, but i would also try obvious number, i.e. .numbers that, when you add 3, gives a perfect square
for example check \(x=1\) and get
\[\sqrt{1+3}+3=1\]
\[2+3=1\] no
try \(x=6\)

Answer 3

so guess at numbers? cause 6 works...