Question

Find the eqaution of the tangent line at (0,0)
y=sinx + sin^2x

Answer 1

can you find the derivative of your function?

Answer 2

yes

Answer 3

ok.... what did you get

Answer 4

y'=2sinx(cosx) + cosx

Answer 5

or cosx(2sinx + 1)

Answer 6

ok... substitute the x value from your point into the derivative... this will give the slope at the point

Answer 7

ok I got 1(0 + 1)

Answer 8

which is 1

Answer 9

so the slope is m = 1

Answer 10

so y = x

Answer 11

thats it... well done

Answer 12

thanks!

Answer 13

the derivative gives that equation of the slope at any point on the curve.

once you have that. Substitute you specific x value to get the slope at the point... then its simply point slope formula

Answer 14

hope it helps

Answer 15

thanks!