(n + 7)^2. I got: 2n² + 14n + 49. Correct?

Question

anonymous · Answer

No, that is not correct.  Not 2n^2 + 14n + 49.  Correct is n^2 + 14n + 49.  Hope that helps.

anonymous · Answer

Oh ok that makes sense, so when your multiplying a letter by a number like this ^2 you keep it single with no numbers infront?

anonymous · Answer

Yes.  Think of the expansion (n + 7) x (n + 7) and then the "2" won't give you any "block".

anonymous · Answer

ah ok, now what about this one (ab + 3)(ab - 3) ?? I'm stuck..

anonymous · Answer

Ok, first, is "ab" one variable or is it a x b?

anonymous · Answer

well the answers show them spaced up like ex. a^2b^2

anonymous · Answer

Ok, then the answer is a^2 x b^2 - 9.  When you have an equation in the form of (w + x)(w - x), then do w^2 - wx + xw - x^2.

anonymous · Answer

The 2 middle terms cancel out to w^2 - x^2.

anonymous · Answer

oh ok, that makes sense now. thank you!