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factor the difference of two squares. 64x2-81y2
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here's a hint... the difference of two squares formula is \[\huge a^2 - b^2 = (a+b)(a-b)\]
does that help?
Start by realizing that the problem is about the difference between two perfect squares. This form in general is: a^2 - b^2 which is factored by (a + b)(a - b). The difference in sign allows ba (which is the same as ab) to cancel with -ab, so that you have 2 terms instead of four. Use this same approach to the above problem.
I don't get it
64x^2-81y^2 (8x)^2 - (9y)^2
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Now, use the formula given by @lgbasallote
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