Question

some one help me pllllllllllllll

Answer 1

Go for it. Ask

Answer 2

find the vertex and find the axis of symmetry
y=-2^2-1

Answer 3

I have forgotten this a bit, but first, is there an x in there?

Answer 4

oh yh srrry

Answer 5

y=-2x^2-1

Answer 6

Cool. know some calculus?

Answer 7

yh

Answer 8

Did you graph it yet?

Answer 9

If you don't want to graph it, you can use \(x = -\frac{b}{2a}\) to get the x-coordinate of the verex

Answer 10

Nice one @Hero In case you forget the equation, and you know calculus, differentiate the equation (to get the gradient), then equate that to zero (since at the vertex the gradient is zero). Working out for x in the equation you get will give you the x-coordinate.

Answer 11

"In case you forget the equation and remember the calculus"...like who would do that

Answer 12

Happened to me once :)

Answer 13

If it can be solved without calculus, then that's the best way to go

Answer 14

True. Just an 'in case measure' @this