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|k/3+2| < or equal to 2
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You'll have two sets of inequalities here: -(k/3+2)<=2 and k/3+2<=2 Know why?
its some rule I know for sure teacher thought it but some one told me to subtract two from each side if im right
First, know how I split the first expression into two?
yup
Good. Now, the target is to have x on one side of the inequality signs. I'll do the first: -(k/3+2)<=2
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Multiply the -ve into the brackets: -k/3-2<=2
Now add 2 to both sides. -k/3<=4
Then comes the part where people make mistakes: Multiply both sides by -3. NOTE: When you multiply or divide both sides by a negative, the INEQUALITY CHANGES DIRECTION: k>=-12
Understand?
mhm thanks
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you're welcome
i still have one more question if you dont mind
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