am trying to factorize 2x^2+9x+4 i.e what can add up to 9 and multiply to be 4
that is not what you need. You need what times to 8 and adds to 9
Don't forget the 2 before the x^2
what you wrote would be right if there was no 2 by the x squared
so this is how its done
\[2x ^{2} +9x +4\]
i mean what can add up to be 9 and multiply to be 4 . this is the question factorize 2x squared+ 9x+ 4x
exactly that is what i meant to write
times the 2 (coefficient) by the constant: 2 times 4 = 8
now take the coefficient of the middle number: 9
ask your self: What times to 8 and adds to 9: 8 and 1 right?
now write it as binomials but remembering the original coefficient: (2x+8)(2x+1)
BUT WAIT
since the first binomial has a common factor of 2 you must divide it by that (2x+8) ----- = (x+4) 2
so factors are (x+4) (2X+1)
thanks so much i got it and i understand it now
Great,
my itunes or android app shows this in video form: www.takebackmath.com
if you want to see it taught
isnt it right if write it this way (2x+1) (x+4) bcs it actually gave me the same thing
yes that is just the same thing write in different order, remember communicative property: a times b = b times a, they give the same answer
ok great
you could be a great help to me bcs to honest my foundation in math is really bad , i am currently taking pre calculus now and i had dropped it for grade w for tow semesters now but this semester i decided to get it done but still having problem in getting it
if you are still there to factorize x^2+2x-2 isnt it (x+2) (x-4)
x^2+2x-8 rather
okay
for this since there is no number beside the x squared you want want times to -8 and adds to 2: 4 times -2 so the factors are (x+4)(x-2)
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