Question

x^2-6=0
why isnt it (x+2) (x-3)=0 just need to know why

Answer 1

because 3*3=9 and not 6

Answer 2

x^2-9 = x^2-3^2 = (x+3)(x-3)

Answer 3

x^2-6 = x^2-9+3 = (x+3)(x-3)+3

Answer 4

typo its suppose to be (x-3) (x+2)

Answer 5

ohh,
(x-3)(x+2) = x^2 -3x+2x -6
=x^2 -x -6
and not x^2 -6

Answer 6

if factored is it (x-3) (x+2) or square root +-6?

Answer 7

roots are \(\large \pm \sqrt6\)
factors are \((x+\sqrt6)(x-\sqrt6) \)

Answer 8

but it is not (x-3) (x+2)

Answer 9

exatly! its not
because (x-3)(x+2) = x^2-x-6

Answer 10

ooh i see

Answer 11

(x-3) (x-2)= x^2-2x-3x+6=x^2-5x+6...so u got an extra 5x

Answer 12

ask if still any doubts.

Answer 13

so when ever it is not a perfect square, i have to to take the square root of both side?

Answer 14

You have to take the square root regardless.

Answer 15

whenever ?
when its in the form of
x^2 - a^2 = 0

Answer 16

then shift a^2 to other side and take square root.

Answer 17

k thanks

Answer 18

welcome :)

Answer 19

bcs u hv 1 exttra x :)

Answer 20

:D