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factor: y^3+27
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Hint: y^3+27 y^3+3^3 Now use the sum of cubes factoring rule
right and i get (y-3)(y^2+3y+3^2)
the sum of cubes factoring formula is x^3+y^3=(x+y)(x^2-xy+y^2)
so you have your signs mixed up
damn... ok so it would be (y+3)(y^2-3y+3^2)
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which becomes (y+3)(y^2-3y+9) after you square that last 3
oh ok you can't leave it squared. thank you!!!
you can still factor it..
not over the rationals
it does not say in R (:
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