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Mathematics
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Factor: 12x^2-96x+120
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take out 12 as a common factor \[12(x^2 - 8x + 12)\] this should allow you to factorise the quadratic in the brackets
oh alright, thanks !
\[12(x^2-8x+10)\]
wouldn't that be correct ?
oops yes... sorry for the mistype
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it's okay, is this the furthest it can be factored?
so the quadratic won't factor
oh okay, thanks again
but pulling out the 12 is factoring (to a point)
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